Расчет дроби 1(3/7) + 1(21/49) = 20/7

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1
3
7
+
1
21
49
=
20
7
2.857
Solution:
1
3
7
+
1
21
49
=
1*7+3
7
+
1*49+21
49
=
7+3
7
+
49+21
49
=
10
7
+
70
49
=
10*7
7*7
+
70
49
=
70
49
+
70
49
=
70+70
49
=
140
49
=
20*7
7*7
=
20
7
2.857
Detailed explanation of the solution:
1.Conversion of mixed fractions to ordinary fractions
1
3
7
+
1
21
49
=
1*7+3
7
+
1*49+21
49
=
7+3
7
+
49+21
49
=
10
7
+
70
49
2.Bringing to a common denominator
10
7
+
70
49
=
10*7
7*7
+
70
49
=
70
49
+
70
49
3.Additionfractions with common denominators
70
49
+
70
49
=
70+70
49
=
140
49
4.Reduce the fraction and get the result
140
49
=
20*7
7*7
=
20
7
2.857
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