This transfer is possible in two ways: direct transfer and using the decimal system.
First we will perform the translation through the decimal system
let\'s translate to decimal like this:
15∙163+10∙162+11∙161+6∙160 = 15∙4096+10∙256+11∙16+6∙1 = 61440+2560+176+6 = 6418210
got It: FAB616 =6418210
Translate the number 6418210 в octal like this:
the Integer part of the number is divided by the base of the new number system:
64182 | 8 | | | | | |
-64176 | 8022 | 8 | | | | |
6 | -8016 | 1002 | 8 | | | |
| 6 | -1000 | 125 | 8 | | |
| | 2 | -120 | 15 | 8 | |
| | | 5 | -8 | 1 | |
| | | | 7 | | |
|
the result of the conversion was:
6418210 = 1752668
the Final answer: FAB616 = 1752668
Now we will perform a direct translation.
let\'s do a direct translation from hexadecimal to binary like this:
FAB616 = F A B 6 = F(=1111) A(=1010) B(=1011) 6(=0110) = 11111010101101102
the Final answer: FAB616 = 11111010101101102
Fill in the number with missing zeros on the left
let\'s make a direct translation from binary to post-binary like this:
0011111010101101102 = 001 111 101 010 110 110 = 001(=1) 111(=7) 101(=5) 010(=2) 110(=6) 110(=6) = 1752668
the Final answer: FAB616 = 1752668