This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s do a direct translation from hexadecimal to binary like this:
156416 = 1 5 6 4 = 1(=0001) 5(=0101) 6(=0110) 4(=0100) = 10101011001002
the Final answer: 156416 = 10101011001002
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
1∙163+5∙162+6∙161+4∙160 = 1∙4096+5∙256+6∙16+4∙1 = 4096+1280+96+4 = 547610
got It: 156416 =547610
Translate the number 547610 в binary like this:
the Integer part of the number is divided by the base of the new number system:
5476 | 2 | | | | | | | | | | | | |
-5476 | 2738 | 2 | | | | | | | | | | | |
0 | -2738 | 1369 | 2 | | | | | | | | | | |
| 0 | -1368 | 684 | 2 | | | | | | | | | |
| | 1 | -684 | 342 | 2 | | | | | | | | |
| | | 0 | -342 | 171 | 2 | | | | | | | |
| | | | 0 | -170 | 85 | 2 | | | | | | |
| | | | | 1 | -84 | 42 | 2 | | | | | |
| | | | | | 1 | -42 | 21 | 2 | | | | |
| | | | | | | 0 | -20 | 10 | 2 | | | |
| | | | | | | | 1 | -10 | 5 | 2 | | |
| | | | | | | | | 0 | -4 | 2 | 2 | |
| | | | | | | | | | 1 | -2 | 1 | |
| | | | | | | | | | | 0 | | |
|
the result of the conversion was:
547610 = 10101011001002
the Final answer: 156416 = 10101011001002