This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
Fill in the number with missing zeros on the left
let\'s make a direct translation from binary to post-binary like this:
001100111101.0012 = 001 100 111 101. 001 = 001(=1) 100(=4) 111(=7) 101(=5). 001(=1) = 1475.18
the Final answer: 1100111101.0012 = 1475.18
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
0∙211+0∙210+1∙29+1∙28+0∙27+0∙26+1∙25+1∙24+1∙23+1∙22+0∙21+1∙20+0∙2-1+0∙2-2+1∙2-3 = 0∙2048+0∙1024+1∙512+1∙256+0∙128+0∙64+1∙32+1∙16+1∙8+1∙4+0∙2+1∙1+0∙0.5+0∙0.25+1∙0.125 = 0+0+512+256+0+0+32+16+8+4+0+1+0+0+0.125 = 829.12510
got It: 001100111101.0012 =829.12510
Translate the number 829.12510 в octal like this:
the Integer part of the number is divided by the base of the new number system:
829 | 8 | | | |
-824 | 103 | 8 | | |
5 | -96 | 12 | 8 | |
| 7 | -8 | 1 | |
| | 4 | | |
|
the Fractional part of the number is multiplied by the base of the new number system:
|
0. | 125*8 |
1 | .0*8 |
the result of the conversion was:
829.12510 = 1475.18
the Final answer: 1100111101.0012 = 1475.18