Transfer 11110101 from binary in octal number system

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This transfer is possible in two ways: direct transfer and using the decimal system.

first, let\'s make a direct transfer.

Fill in the number with missing zeros on the left

let\'s make a direct translation from binary to post-binary like this:

0111101012 = 011 110 101 = 011(=3) 110(=6) 101(=5) = 3658

the Final answer: 111101012 = 3658

now let\'s make the transfer using the decimal system.

let\'s translate to decimal like this:

0∙28+1∙27+1∙26+1∙25+1∙24+0∙23+1∙22+0∙21+1∙20 = 0∙256+1∙128+1∙64+1∙32+1∙16+0∙8+1∙4+0∙2+1∙1 = 0+128+64+32+16+0+4+0+1 = 24510

got It: 0111101012 =24510

Translate the number 24510 в octal like this:

the Integer part of the number is divided by the base of the new number system:

2458
-240308
5-243
6
Перевод чисел из одной системы счисления в другую

the result of the conversion was:

24510 = 3658
the Final answer: 111101012 = 3658
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