This transfer is possible in two ways: direct transfer and using the decimal system.
First we will perform the translation through the decimal system
let\'s translate to decimal like this:
7∙163+13∙162+5∙161+10∙160 = 7∙4096+13∙256+5∙16+10∙1 = 28672+3328+80+10 = 3209010
got It: 7D5A16 =3209010
Translate the number 3209010 в octal like this:
the Integer part of the number is divided by the base of the new number system:
32090 | 8 | | | | |
-32088 | 4011 | 8 | | | |
2 | -4008 | 501 | 8 | | |
| 3 | -496 | 62 | 8 | |
| | 5 | -56 | 7 | |
| | | 6 | | |
|
the result of the conversion was:
3209010 = 765328
the Final answer: 7D5A16 = 765328
Now we will perform a direct translation.
let\'s do a direct translation from hexadecimal to binary like this:
7D5A16 = 7 D 5 A = 7(=0111) D(=1101) 5(=0101) A(=1010) = 1111101010110102
the Final answer: 7D5A16 = 1111101010110102
let\'s make a direct translation from binary to post-binary like this:
1111101010110102 = 111 110 101 011 010 = 111(=7) 110(=6) 101(=5) 011(=3) 010(=2) = 765328
the Final answer: 7D5A16 = 765328