This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s do a direct translation from hexadecimal to binary like this:
B216 = B 2 = B(=1011) 2(=0010) = 101100102
the Final answer: B216 = 101100102
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
11∙161+2∙160 = 11∙16+2∙1 = 176+2 = 17810
got It: B216 =17810
Translate the number 17810 в binary like this:
the Integer part of the number is divided by the base of the new number system:
178 | 2 | | | | | | | |
-178 | 89 | 2 | | | | | | |
0 | -88 | 44 | 2 | | | | | |
| 1 | -44 | 22 | 2 | | | | |
| | 0 | -22 | 11 | 2 | | | |
| | | 0 | -10 | 5 | 2 | | |
| | | | 1 | -4 | 2 | 2 | |
| | | | | 1 | -2 | 1 | |
| | | | | | 0 | | |
|
the result of the conversion was:
17810 = 101100102
the Final answer: B216 = 101100102