This transfer is possible in two ways: direct transfer and using the decimal system.
First we will perform the translation through the decimal system
let\'s translate to decimal like this:
2∙162+0∙161+10∙160+0∙16-1+14∙16-2 = 2∙256+0∙16+10∙1+0∙0.0625+14∙0.00390625 = 512+0+10+0+0.0546875 = 522.054687510
got It: 20A.0E16 =522.054687510
Translate the number 522.054687510 в octal like this:
the Integer part of the number is divided by the base of the new number system:
522 | 8 | | | |
-520 | 65 | 8 | | |
2 | -64 | 8 | 8 | |
| 1 | -8 | 1 | |
| | 0 | | |
|
the Fractional part of the number is multiplied by the base of the new number system:
|
0. | 0546875*8 |
0 | .4375*8 |
3 | .5*8 |
4 | .0*8 |
the result of the conversion was:
522.054687510 = 1012.0348
the Final answer: 20A.0E16 = 1012.0348
Now we will perform a direct translation.
let\'s do a direct translation from hexadecimal to binary like this:
20A.0E16 = 2 0 A. 0 E = 2(=0010) 0(=0000) A(=1010). 0(=0000) E(=1110) = 1000001010.00001112
the Final answer: 20A.0E16 = 1000001010.00001112
Fill in the number with missing zeros on the left
Fill in the number with missing zeros on the right
let\'s make a direct translation from binary to post-binary like this:
001000001010.0000111002 = 001 000 001 010. 000 011 100 = 001(=1) 000(=0) 001(=1) 010(=2). 000(=0) 011(=3) 100(=4) = 1012.0348
the Final answer: 20A.0E16 = 1012.0348