# Transfer 00010110 from binary in octal number system

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This transfer is possible in two ways: direct transfer and using the decimal system.

first, let\'s make a direct transfer.

Fill in the number with missing zeros on the left

let\'s make a direct translation from binary to post-binary like this:

0000101102 = 000 010 110 = 000(=0) 010(=2) 110(=6) = 0268

the Final answer: 000101102 = 0268

now let\'s make the transfer using the decimal system.

let\'s translate to decimal like this:

0∙28+0∙27+0∙26+0∙25+1∙24+0∙23+1∙22+1∙21+0∙20 = 0∙256+0∙128+0∙64+0∙32+1∙16+0∙8+1∙4+1∙2+0∙1 = 0+0+0+0+16+0+4+2+0 = 2210

got It: 0000101102 =2210

Translate the number 2210 в octal like this:

the Integer part of the number is divided by the base of the new number system:

 22 8 -16 2 6 the result of the conversion was:

2210 = 268
the Final answer: 000101102 = 268
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