This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
Fill in the number with missing zeros on the left
let\'s make a direct translation from binary to post-binary like this:
0000010102 = 000 001 010 = 000(=0) 001(=1) 010(=2) = 0128
the Final answer: 00010102 = 0128
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
0∙28+0∙27+0∙26+0∙25+0∙24+1∙23+0∙22+1∙21+0∙20 = 0∙256+0∙128+0∙64+0∙32+0∙16+1∙8+0∙4+1∙2+0∙1 = 0+0+0+0+0+8+0+2+0 = 1010
got It: 0000010102 =1010
Translate the number 1010 в octal like this:
the Integer part of the number is divided by the base of the new number system:
10 | 8 | |
-8 | 1 | |
2 | | |
 |
the result of the conversion was:
1010 = 128
the Final answer: 00010102 = 128