This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s do a direct translation from hexadecimal to binary like this:
3E816 = 3 E 8 = 3(=0011) E(=1110) 8(=1000) = 11111010002
the Final answer: 3E816 = 11111010002
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
3∙162+14∙161+8∙160 = 3∙256+14∙16+8∙1 = 768+224+8 = 100010
got It: 3E816 =100010
Translate the number 100010 в binary like this:
the Integer part of the number is divided by the base of the new number system:
1000 | 2 | | | | | | | | | |
-1000 | 500 | 2 | | | | | | | | |
0 | -500 | 250 | 2 | | | | | | | |
| 0 | -250 | 125 | 2 | | | | | | |
| | 0 | -124 | 62 | 2 | | | | | |
| | | 1 | -62 | 31 | 2 | | | | |
| | | | 0 | -30 | 15 | 2 | | | |
| | | | | 1 | -14 | 7 | 2 | | |
| | | | | | 1 | -6 | 3 | 2 | |
| | | | | | | 1 | -2 | 1 | |
| | | | | | | | 1 | | |
|
the result of the conversion was:
100010 = 11111010002
the Final answer: 3E816 = 11111010002