This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s translate to decimal like this:
3∙82+4∙81+5∙80 = 3∙64+4∙8+5∙1 = 192+32+5 = 22910
got It: 3458 =22910
Translate the number 22910 в hexadecimal like this:
the Integer part of the number is divided by the base of the new number system:
229 | 16 | |
-224 | E | |
5 | | |
 |
the result of the conversion was:
22910 = E516
the Final answer: 3458 = E516
now let\'s make the transfer using the decimal system.
let\'s do a direct translation from octal to binary like this:
3458 = 3 4 5 = 3(=011) 4(=100) 5(=101) = 0111001012
the Final answer: 3458 = 111001012
let\'s do a direct translation from binary to hexadecimal like this:
111001012 = 1110 0101 = 1110(=E) 0101(=5) = E516
the Final answer: 111001018 = E516