This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s do a direct translation from hexadecimal to binary like this:
16E0216 = 1 6 E 0 2 = 1(=0001) 6(=0110) E(=1110) 0(=0000) 2(=0010) = 101101110000000102
the Final answer: 16E0216 = 101101110000000102
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
1∙164+6∙163+14∙162+0∙161+2∙160 = 1∙65536+6∙4096+14∙256+0∙16+2∙1 = 65536+24576+3584+0+2 = 9369810
got It: 16E0216 =9369810
Translate the number 9369810 в binary like this:
the Integer part of the number is divided by the base of the new number system:
93698 | 2 | | | | | | | | | | | | | | | | |
-93698 | 46849 | 2 | | | | | | | | | | | | | | | |
0 | -46848 | 23424 | 2 | | | | | | | | | | | | | | |
| 1 | -23424 | 11712 | 2 | | | | | | | | | | | | | |
| | 0 | -11712 | 5856 | 2 | | | | | | | | | | | | |
| | | 0 | -5856 | 2928 | 2 | | | | | | | | | | | |
| | | | 0 | -2928 | 1464 | 2 | | | | | | | | | | |
| | | | | 0 | -1464 | 732 | 2 | | | | | | | | | |
| | | | | | 0 | -732 | 366 | 2 | | | | | | | | |
| | | | | | | 0 | -366 | 183 | 2 | | | | | | | |
| | | | | | | | 0 | -182 | 91 | 2 | | | | | | |
| | | | | | | | | 1 | -90 | 45 | 2 | | | | | |
| | | | | | | | | | 1 | -44 | 22 | 2 | | | | |
| | | | | | | | | | | 1 | -22 | 11 | 2 | | | |
| | | | | | | | | | | | 0 | -10 | 5 | 2 | | |
| | | | | | | | | | | | | 1 | -4 | 2 | 2 | |
| | | | | | | | | | | | | | 1 | -2 | 1 | |
| | | | | | | | | | | | | | | 0 | | |
|
the result of the conversion was:
9369810 = 101101110000000102
the Final answer: 16E0216 = 101101110000000102