This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s do a direct translation from hexadecimal to binary like this:
2F.316 = 2 F. 3 = 2(=0010) F(=1111). 3(=0011) = 101111.00112
the Final answer: 2F.316 = 101111.00112
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
2∙161+15∙160+3∙16-1 = 2∙16+15∙1+3∙0.0625 = 32+15+0.1875 = 47.187510
got It: 2F.316 =47.187510
Translate the number 47.187510 в binary like this:
the Integer part of the number is divided by the base of the new number system:
47 | 2 | | | | | |
-46 | 23 | 2 | | | | |
1 | -22 | 11 | 2 | | | |
| 1 | -10 | 5 | 2 | | |
| | 1 | -4 | 2 | 2 | |
| | | 1 | -2 | 1 | |
| | | | 0 | | |
|
the Fractional part of the number is multiplied by the base of the new number system:
|
0. | 1875*2 |
0 | .375*2 |
0 | .75*2 |
1 | .5*2 |
1 | .0*2 |
the result of the conversion was:
47.187510 = 101111.00112
the Final answer: 2F.316 = 101111.00112