This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s do a direct translation from octal to binary like this:
2178 = 2 1 7 = 2(=010) 1(=001) 7(=111) = 0100011112
the Final answer: 2178 = 100011112
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
2∙82+1∙81+7∙80 = 2∙64+1∙8+7∙1 = 128+8+7 = 14310
got It: 2178 =14310
Translate the number 14310 в binary like this:
the Integer part of the number is divided by the base of the new number system:
143 | 2 | | | | | | | |
-142 | 71 | 2 | | | | | | |
1 | -70 | 35 | 2 | | | | | |
| 1 | -34 | 17 | 2 | | | | |
| | 1 | -16 | 8 | 2 | | | |
| | | 1 | -8 | 4 | 2 | | |
| | | | 0 | -4 | 2 | 2 | |
| | | | | 0 | -2 | 1 | |
| | | | | | 0 | | |
|
the result of the conversion was:
14310 = 100011112
the Final answer: 2178 = 100011112