This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s do a direct translation from hexadecimal to binary like this:
FE916 = F E 9 = F(=1111) E(=1110) 9(=1001) = 1111111010012
the Final answer: FE916 = 1111111010012
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
15∙162+14∙161+9∙160 = 15∙256+14∙16+9∙1 = 3840+224+9 = 407310
got It: FE916 =407310
Translate the number 407310 в binary like this:
the Integer part of the number is divided by the base of the new number system:
4073 | 2 | | | | | | | | | | | |
-4072 | 2036 | 2 | | | | | | | | | | |
1 | -2036 | 1018 | 2 | | | | | | | | | |
| 0 | -1018 | 509 | 2 | | | | | | | | |
| | 0 | -508 | 254 | 2 | | | | | | | |
| | | 1 | -254 | 127 | 2 | | | | | | |
| | | | 0 | -126 | 63 | 2 | | | | | |
| | | | | 1 | -62 | 31 | 2 | | | | |
| | | | | | 1 | -30 | 15 | 2 | | | |
| | | | | | | 1 | -14 | 7 | 2 | | |
| | | | | | | | 1 | -6 | 3 | 2 | |
| | | | | | | | | 1 | -2 | 1 | |
| | | | | | | | | | 1 | | |
|
the result of the conversion was:
407310 = 1111111010012
the Final answer: FE916 = 1111111010012