This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
Fill in the number with missing zeros on the left
let\'s make a direct translation from binary to post-binary like this:
0000011012 = 000 001 101 = 000(=0) 001(=1) 101(=5) = 0158
the Final answer: 00011012 = 0158
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
0∙28+0∙27+0∙26+0∙25+0∙24+1∙23+1∙22+0∙21+1∙20 = 0∙256+0∙128+0∙64+0∙32+0∙16+1∙8+1∙4+0∙2+1∙1 = 0+0+0+0+0+8+4+0+1 = 1310
got It: 0000011012 =1310
Translate the number 1310 в octal like this:
the Integer part of the number is divided by the base of the new number system:
13 | 8 | |
-8 | 1 | |
5 | | |
|
the result of the conversion was:
1310 = 158
the Final answer: 00011012 = 158