Transfer 1110001011 from binary in octal number system

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This transfer is possible in two ways: direct transfer and using the decimal system.

first, let\'s make a direct transfer.

Fill in the number with missing zeros on the left

let\'s make a direct translation from binary to post-binary like this:

0011100010112 = 001 110 001 011 = 001(=1) 110(=6) 001(=1) 011(=3) = 16138

the Final answer: 11100010112 = 16138

now let\'s make the transfer using the decimal system.

let\'s translate to decimal like this:

0∙211+0∙210+1∙29+1∙28+1∙27+0∙26+0∙25+0∙24+1∙23+0∙22+1∙21+1∙20 = 0∙2048+0∙1024+1∙512+1∙256+1∙128+0∙64+0∙32+0∙16+1∙8+0∙4+1∙2+1∙1 = 0+0+512+256+128+0+0+0+8+0+2+1 = 90710

got It: 0011100010112 =90710

Translate the number 90710 в octal like this:

the Integer part of the number is divided by the base of the new number system:

9078
-9041138
3-112148
1-81
6
Перевод чисел из одной системы счисления в другую

the result of the conversion was:

90710 = 16138
the Final answer: 11100010112 = 16138
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