This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s do a direct translation from hexadecimal to binary like this:
3A.5B16 = 3 A. 5 B = 3(=0011) A(=1010). 5(=0101) B(=1011) = 111010.010110112
the Final answer: 3A.5B16 = 111010.010110112
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
3∙161+10∙160+5∙16-1+11∙16-2 = 3∙16+10∙1+5∙0.0625+11∙0.00390625 = 48+10+0.3125+0.04296875 = 58.3554687510
got It: 3A.5B16 =58.3554687510
Translate the number 58.3554687510 в binary like this:
the Integer part of the number is divided by the base of the new number system:
58 | 2 | | | | | |
-58 | 29 | 2 | | | | |
0 | -28 | 14 | 2 | | | |
| 1 | -14 | 7 | 2 | | |
| | 0 | -6 | 3 | 2 | |
| | | 1 | -2 | 1 | |
| | | | 1 | | |
|
the Fractional part of the number is multiplied by the base of the new number system:
|
0. | 35546875*2 |
0 | .71094*2 |
1 | .42188*2 |
0 | .84375*2 |
1 | .6875*2 |
1 | .375*2 |
0 | .75*2 |
1 | .5*2 |
1 | .0*2 |
the result of the conversion was:
58.3554687510 = 111010.010110112
the Final answer: 3A.5B16 = 111010.010110112