This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
Fill in the number with missing zeros on the left
Fill in the number with missing zeros on the right
let\'s make a direct translation from binary to post-binary like this:
001011.0110011002 = 001 011. 011 001 100 = 001(=1) 011(=3). 011(=3) 001(=1) 100(=4) = 13.3148
the Final answer: 1011.01100112 = 13.3148
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
0∙25+0∙24+1∙23+0∙22+1∙21+1∙20+0∙2-1+1∙2-2+1∙2-3+0∙2-4+0∙2-5+1∙2-6+1∙2-7+0∙2-8+0∙2-9 = 0∙32+0∙16+1∙8+0∙4+1∙2+1∙1+0∙0.5+1∙0.25+1∙0.125+0∙0.0625+0∙0.03125+1∙0.015625+1∙0.0078125+0∙0.00390625+0∙0.001953125 = 0+0+8+0+2+1+0+0.25+0.125+0+0+0.015625+0.0078125+0+0 = 11.398437510
got It: 001011.0110011002 =11.398437510
Translate the number 11.398437510 в octal like this:
the Integer part of the number is divided by the base of the new number system:
11 | 8 | |
-8 | 1 | |
3 | | |
|
the Fractional part of the number is multiplied by the base of the new number system:
|
0. | 3984375*8 |
3 | .1875*8 |
1 | .5*8 |
4 | .0*8 |
the result of the conversion was:
11.398437510 = 13.3148
the Final answer: 1011.01100112 = 13.3148