This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
Fill in the number with missing zeros on the left
Fill in the number with missing zeros on the right
let\'s do a direct translation from binary to hexadecimal like this:
000110111011.0010101000002 = 0001 1011 1011. 0010 1010 0000 = 0001(=1) 1011(=B) 1011(=B). 0010(=2) 1010(=A) 0000(=0) = 1BB.2A016
the Final answer: 000110111011.0010101000002 = 1BB.2A016
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
0∙211+0∙210+0∙29+1∙28+1∙27+0∙26+1∙25+1∙24+1∙23+0∙22+1∙21+1∙20+0∙2-1+0∙2-2+1∙2-3+0∙2-4+1∙2-5+0∙2-6+1∙2-7+0∙2-8+0∙2-9+0∙2-10+0∙2-11+0∙2-12 = 0∙2048+0∙1024+0∙512+1∙256+1∙128+0∙64+1∙32+1∙16+1∙8+0∙4+1∙2+1∙1+0∙0.5+0∙0.25+1∙0.125+0∙0.0625+1∙0.03125+0∙0.015625+1∙0.0078125+0∙0.00390625+0∙0.001953125+0∙0.0009765625+0∙0.00048828125+0∙0.000244140625 = 0+0+0+256+128+0+32+16+8+0+2+1+0+0+0.125+0+0.03125+0+0.0078125+0+0+0+0+0 = 443.164062510
got It: 000110111011.0010101000002 =443.164062510
Translate the number 443.164062510 в hexadecimal like this:
the Integer part of the number is divided by the base of the new number system:
| 443 | 16 | | |
| -432 | 27 | 16 | |
| B | -16 | 1 | |
| B | | |
 |
the Fractional part of the number is multiplied by the base of the new number system:
 |
| 0. | 1640625*16 |
| 2 | .625*16 |
| A | .0*16 |
the result of the conversion was:
443.164062510 = 1BB.2A16
the Final answer: 000110111011.0010101000002 = 1BB.2A16