This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
Fill in the number with missing zeros on the left
let\'s make a direct translation from binary to post-binary like this:
001101.1101112 = 001 101. 110 111 = 001(=1) 101(=5). 110(=6) 111(=7) = 15.678
the Final answer: 01101.1101112 = 15.678
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
0∙25+0∙24+1∙23+1∙22+0∙21+1∙20+1∙2-1+1∙2-2+0∙2-3+1∙2-4+1∙2-5+1∙2-6 = 0∙32+0∙16+1∙8+1∙4+0∙2+1∙1+1∙0.5+1∙0.25+0∙0.125+1∙0.0625+1∙0.03125+1∙0.015625 = 0+0+8+4+0+1+0.5+0.25+0+0.0625+0.03125+0.015625 = 13.85937510
got It: 001101.1101112 =13.85937510
Translate the number 13.85937510 в octal like this:
the Integer part of the number is divided by the base of the new number system:
| 13 | 8 | |
| -8 | 1 | |
| 5 | | |
 |
the Fractional part of the number is multiplied by the base of the new number system:
 |
| 0. | 859375*8 |
| 6 | .875*8 |
| 7 | .0*8 |
the result of the conversion was:
13.85937510 = 15.678
the Final answer: 01101.1101112 = 15.678