This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
Fill in the number with missing zeros on the left
let\'s make a direct translation from binary to postbinary like this:
001101.110111_{2} = 001 101. 110 111 = 001_{(=1)} 101_{(=5)}. 110_{(=6)} 111_{(=7)} = 15.67_{8}
the Final answer: 01101.110111_{2} = 15.67_{8}
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
0∙2^{5}+0∙2^{4}+1∙2^{3}+1∙2^{2}+0∙2^{1}+1∙2^{0}+1∙2^{1}+1∙2^{2}+0∙2^{3}+1∙2^{4}+1∙2^{5}+1∙2^{6} = 0∙32+0∙16+1∙8+1∙4+0∙2+1∙1+1∙0.5+1∙0.25+0∙0.125+1∙0.0625+1∙0.03125+1∙0.015625 = 0+0+8+4+0+1+0.5+0.25+0+0.0625+0.03125+0.015625 = 13.859375_{10}
got It: 001101.110111_{2} =13.859375_{10}
Translate the number 13.859375_{10} в octal like this:
the Integer part of the number is divided by the base of the new number system:
13  8  
8  1  
5   

the Fractional part of the number is multiplied by the base of the new number system:

0.  859375*8 
6  .875*8 
7  .0*8 
the result of the conversion was:
13.859375_{10} = 15.67_{8}
the Final answer: 01101.110111_{2} = 15.67_{8}