This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s translate to decimal like this:
2∙82+4∙81+1∙80 = 2∙64+4∙8+1∙1 = 128+32+1 = 16110
got It: 2418 =16110
Translate the number 16110 в hexadecimal like this:
the Integer part of the number is divided by the base of the new number system:
161 | 16 | |
-160 | A | |
1 | | |
|
the result of the conversion was:
16110 = A116
the Final answer: 2418 = A116
now let\'s make the transfer using the decimal system.
let\'s do a direct translation from octal to binary like this:
2418 = 2 4 1 = 2(=010) 4(=100) 1(=001) = 0101000012
the Final answer: 2418 = 101000012
let\'s do a direct translation from binary to hexadecimal like this:
101000012 = 1010 0001 = 1010(=A) 0001(=1) = A116
the Final answer: 101000018 = A116