This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
Fill in the number with missing zeros on the right
let\'s make a direct translation from binary to post-binary like this:
110111110111001.1101111100101002 = 110 111 110 111 001. 110 111 110 010 100 = 110(=6) 111(=7) 110(=6) 111(=7) 001(=1). 110(=6) 111(=7) 110(=6) 010(=2) 100(=4) = 67671.676248
the Final answer: 110111110111001.11011111001012 = 67671.676248
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
1∙214+1∙213+0∙212+1∙211+1∙210+1∙29+1∙28+1∙27+0∙26+1∙25+1∙24+1∙23+0∙22+0∙21+1∙20+1∙2-1+1∙2-2+0∙2-3+1∙2-4+1∙2-5+1∙2-6+1∙2-7+1∙2-8+0∙2-9+0∙2-10+1∙2-11+0∙2-12+1∙2-13+0∙2-14+0∙2-15 = 1∙16384+1∙8192+0∙4096+1∙2048+1∙1024+1∙512+1∙256+1∙128+0∙64+1∙32+1∙16+1∙8+0∙4+0∙2+1∙1+1∙0.5+1∙0.25+0∙0.125+1∙0.0625+1∙0.03125+1∙0.015625+1∙0.0078125+1∙0.00390625+0∙0.001953125+0∙0.0009765625+1∙0.00048828125+0∙0.000244140625+1∙0.0001220703125+0∙6.103515625E-5+0∙3.0517578125E-5 = 16384+8192+0+2048+1024+512+256+128+0+32+16+8+0+0+1+0.5+0.25+0+0.0625+0.03125+0.015625+0.0078125+0.00390625+0+0+0.00048828125+0+0.0001220703125+0+0 = 28601.871704101562510
got It: 110111110111001.1101111100101002 =28601.871704101562510
Translate the number 28601.871704101562510 в octal like this:
the Integer part of the number is divided by the base of the new number system:
28601 | 8 | | | | |
-28600 | 3575 | 8 | | | |
1 | -3568 | 446 | 8 | | |
| 7 | -440 | 55 | 8 | |
| | 6 | -48 | 6 | |
| | | 7 | | |
|
the Fractional part of the number is multiplied by the base of the new number system:
|
0. | 8717041015625*8 |
6 | .97363*8 |
7 | .78906*8 |
6 | .3125*8 |
2 | .5*8 |
4 | .0*8 |
the result of the conversion was:
28601.871704101562510 = 67671.676248
the Final answer: 110111110111001.11011111001012 = 67671.676248