This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s do a direct translation from hexadecimal to binary like this:
A5D16 = A 5 D = A(=1010) 5(=0101) D(=1101) = 1010010111012
the Final answer: A5D16 = 1010010111012
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
10∙162+5∙161+13∙160 = 10∙256+5∙16+13∙1 = 2560+80+13 = 265310
got It: A5D16 =265310
Translate the number 265310 в binary like this:
the Integer part of the number is divided by the base of the new number system:
2653 | 2 | | | | | | | | | | | |
-2652 | 1326 | 2 | | | | | | | | | | |
1 | -1326 | 663 | 2 | | | | | | | | | |
| 0 | -662 | 331 | 2 | | | | | | | | |
| | 1 | -330 | 165 | 2 | | | | | | | |
| | | 1 | -164 | 82 | 2 | | | | | | |
| | | | 1 | -82 | 41 | 2 | | | | | |
| | | | | 0 | -40 | 20 | 2 | | | | |
| | | | | | 1 | -20 | 10 | 2 | | | |
| | | | | | | 0 | -10 | 5 | 2 | | |
| | | | | | | | 0 | -4 | 2 | 2 | |
| | | | | | | | | 1 | -2 | 1 | |
| | | | | | | | | | 0 | | |
|
the result of the conversion was:
265310 = 1010010111012
the Final answer: A5D16 = 1010010111012