This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
Fill in the number with missing zeros on the left
let\'s do a direct translation from binary to hexadecimal like this:
00010010111101012 = 0001 0010 1111 0101 = 0001(=1) 0010(=2) 1111(=F) 0101(=5) = 12F516
the Final answer: 00010010111101012 = 12F516
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
0∙215+0∙214+0∙213+1∙212+0∙211+0∙210+1∙29+0∙28+1∙27+1∙26+1∙25+1∙24+0∙23+1∙22+0∙21+1∙20 = 0∙32768+0∙16384+0∙8192+1∙4096+0∙2048+0∙1024+1∙512+0∙256+1∙128+1∙64+1∙32+1∙16+0∙8+1∙4+0∙2+1∙1 = 0+0+0+4096+0+0+512+0+128+64+32+16+0+4+0+1 = 485310
got It: 00010010111101012 =485310
Translate the number 485310 в hexadecimal like this:
the Integer part of the number is divided by the base of the new number system:
4853 | 16 | | | |
-4848 | 303 | 16 | | |
5 | -288 | 18 | 16 | |
| F | -16 | 1 | |
| | 2 | | |
|
the result of the conversion was:
485310 = 12F516
the Final answer: 00010010111101012 = 12F516