# Transfer 10100.01110111 from binary in octal number system

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This transfer is possible in two ways: direct transfer and using the decimal system.

first, let\'s make a direct transfer.

Fill in the number with missing zeros on the left

Fill in the number with missing zeros on the right

let\'s make a direct translation from binary to post-binary like this:

010100.0111011102 = 010 100. 011 101 110 = 010(=2) 100(=4). 011(=3) 101(=5) 110(=6) = 24.3568

the Final answer: 10100.011101112 = 24.3568

now let\'s make the transfer using the decimal system.

let\'s translate to decimal like this:

0∙25+1∙24+0∙23+1∙22+0∙21+0∙20+0∙2-1+1∙2-2+1∙2-3+1∙2-4+0∙2-5+1∙2-6+1∙2-7+1∙2-8+0∙2-9 = 0∙32+1∙16+0∙8+1∙4+0∙2+0∙1+0∙0.5+1∙0.25+1∙0.125+1∙0.0625+0∙0.03125+1∙0.015625+1∙0.0078125+1∙0.00390625+0∙0.001953125 = 0+16+0+4+0+0+0+0.25+0.125+0.0625+0+0.015625+0.0078125+0.00390625+0 = 20.4648437510

got It: 010100.0111011102 =20.4648437510

Translate the number 20.4648437510 в octal like this:

the Integer part of the number is divided by the base of the new number system:

 20 8 -16 2 4 the Fractional part of the number is multiplied by the base of the new number system: 0. 46484375*8 3 .71875*8 5 .75*8 6 .0*8

the result of the conversion was:

20.4648437510 = 24.3568
the Final answer: 10100.011101112 = 24.3568
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