This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
Fill in the number with missing zeros on the left
let\'s do a direct translation from binary to hexadecimal like this:
0001101101102 = 0001 1011 0110 = 0001(=1) 1011(=B) 0110(=6) = 1B616
the Final answer: 0001101101102 = 1B616
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
0∙211+0∙210+0∙29+1∙28+1∙27+0∙26+1∙25+1∙24+0∙23+1∙22+1∙21+0∙20 = 0∙2048+0∙1024+0∙512+1∙256+1∙128+0∙64+1∙32+1∙16+0∙8+1∙4+1∙2+0∙1 = 0+0+0+256+128+0+32+16+0+4+2+0 = 43810
got It: 0001101101102 =43810
Translate the number 43810 в hexadecimal like this:
the Integer part of the number is divided by the base of the new number system:
438 | 16 | | |
-432 | 27 | 16 | |
6 | -16 | 1 | |
| B | | |
|
the result of the conversion was:
43810 = 1B616
the Final answer: 0001101101102 = 1B616