This transfer is possible in two ways: direct transfer and using the decimal system.
First we will perform the translation through the decimal system
let\'s translate to decimal like this:
4∙162+5∙161+7∙160 = 4∙256+5∙16+7∙1 = 1024+80+7 = 111110
got It: 45716 =111110
Translate the number 111110 в octal like this:
the Integer part of the number is divided by the base of the new number system:
1111 | 8 | | | |
-1104 | 138 | 8 | | |
7 | -136 | 17 | 8 | |
| 2 | -16 | 2 | |
| | 1 | | |
|
the result of the conversion was:
111110 = 21278
the Final answer: 45716 = 21278
Now we will perform a direct translation.
let\'s do a direct translation from hexadecimal to binary like this:
45716 = 4 5 7 = 4(=0100) 5(=0101) 7(=0111) = 100010101112
the Final answer: 45716 = 100010101112
Fill in the number with missing zeros on the left
let\'s make a direct translation from binary to post-binary like this:
0100010101112 = 010 001 010 111 = 010(=2) 001(=1) 010(=2) 111(=7) = 21278
the Final answer: 45716 = 21278