https://binary2hex.com/numberconverter.html?id=26581
# Transfer 0203 from hexadecimal in binary number system

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case '6':maxlenght = 8*tip; break;
case '7':maxlenght = 0*tip; break;
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if (ss==3) {strFilter =/^[0-7,.]*$/; text=" an Octal number can only contain digits 0-7, as well as a dot for fractional numbers"; }
if (ss==4) {strFilter =/^[0-9,.-]*$/; text=" a Decimal number can only contain digits 0-9, as well as a dot for fractional numbers"; }
if (ss==5) {strFilter =/^[0-9a-fA-F,.x]*$/; text=" a Hexadecimal number can only contain digits 0-9, letters A, B,C,D, E,F, and a dot for fractional numbers";}
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alert(" a Binary number can only contain the digits 0 and 1, as well as a dot for fractional numbers");
$('#chislo').val('');
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$('input[name=submit]').val(" data Transfer, wait");
$('input[name=submit]').prop('disabled',true);
$('#text_perevod').fadeOut(1);
$('#href_calc').fadeOut(1);
// отправляем форму
$.ajax({
type:"POST",
data: {
chislo: $('#chislo').val(),
ss: $('input[name=ss]:checked').val(),
ssTo: $('input[name=ssTo]:checked').val(),
ssbcd: $('input[name=ssbcd]:checked').val(),
ssTobcd: $('input[name=ssTobcd]:checked').val(),
ssdr: $('#ssdr').val(),
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ssDop: $('input[name=ssDop]:checked').val(),
sssign: $('input[name=sssign]:checked').val(),
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ssTotip: $('input[name=ssTotip]:checked').val(),
ssTotipsign: $('input[name=ssTotipsign]:checked').val(),
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url: "https://binary2hex.com/calc/calcyadro.php?calculator=2&calcid=1",
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}
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Ternary

Octal

Decimal

Hexadecimal

Binary-decimal

Other

Additional

Binary

Triple

Octal

Decimal

Hexadecimal

Binary-decimal

Other

Additional

$( function() {
window.print();
});

Enter a number:

His number system:

Binary Ternary

Octal

Decimal

Hexadecimal

Binary-decimal

Other

Additional

Translate to :

by triads

by notebooks

by notebooks

let\'s translate to decimal like this:

0∙16^{3}+2∙16^{2}+0∙16^{1}+3∙16^{0} = 0∙4096+2∙256+0∙16+3∙1 = 0+512+0+3 = 515_{10}

got It: 0203_{16} =515_{10}

let\'s translate from decimal to binary decimal (BCD) like this:

515_{10} = 5 1 5 = 5_{(=0101)} 1_{(=0001)} 5_{(=0101)} = 10100010101_{BCD}

the Final answer: 0203_{16} = 10100010101_{BCD}

Permanent link to the result of this calculation