This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s translate to decimal like this:
1∙82+4∙81+3∙80+5∙8-1+6∙8-2 = 1∙64+4∙8+3∙1+5∙0.125+6∙0.015625 = 64+32+3+0.625+0.09375 = 99.7187510
got It: 143.568 =99.7187510
Translate the number 99.7187510 в hexadecimal like this:
the Integer part of the number is divided by the base of the new number system:
99 | 16 | |
-96 | 6 | |
3 | | |
|
the Fractional part of the number is multiplied by the base of the new number system:
|
0. | 71875*16 |
B | .5*16 |
8 | .0*16 |
the result of the conversion was:
99.7187510 = 63.B816
the Final answer: 143.568 = 63.B816
now let\'s make the transfer using the decimal system.
let\'s do a direct translation from octal to binary like this:
143.568 = 1 4 3. 5 6 = 1(=001) 4(=100) 3(=011). 5(=101) 6(=110) = 001100011.1011102
the Final answer: 143.568 = 1100011.101112
Fill in the number with missing zeros on the left
Fill in the number with missing zeros on the right
let\'s do a direct translation from binary to hexadecimal like this:
01100011.101110002 = 0110 0011. 1011 1000 = 0110(=6) 0011(=3). 1011(=B) 1000(=8) = 63.B816
the Final answer: 01100011.101110008 = 63.B816