let\'s translate to decimal like this:
0∙57+1∙56+0∙55+0∙54+0∙53+1∙52+0∙51+1∙50 = 0∙78125+1∙15625+0∙3125+0∙625+0∙125+1∙25+0∙5+1∙1 = 0+15625+0+0+0+25+0+1 = 1565110
got It: 010001015 =1565110
Translate the number 1565110 в binary like this:
the Integer part of the number is divided by the base of the new number system:
15651 | 2 | | | | | | | | | | | | | |
-15650 | 7825 | 2 | | | | | | | | | | | | |
1 | -7824 | 3912 | 2 | | | | | | | | | | | |
| 1 | -3912 | 1956 | 2 | | | | | | | | | | |
| | 0 | -1956 | 978 | 2 | | | | | | | | | |
| | | 0 | -978 | 489 | 2 | | | | | | | | |
| | | | 0 | -488 | 244 | 2 | | | | | | | |
| | | | | 1 | -244 | 122 | 2 | | | | | | |
| | | | | | 0 | -122 | 61 | 2 | | | | | |
| | | | | | | 0 | -60 | 30 | 2 | | | | |
| | | | | | | | 1 | -30 | 15 | 2 | | | |
| | | | | | | | | 0 | -14 | 7 | 2 | | |
| | | | | | | | | | 1 | -6 | 3 | 2 | |
| | | | | | | | | | | 1 | -2 | 1 | |
| | | | | | | | | | | | 1 | | |
|
the result of the conversion was:
1565110 = 111101001000112
the Final answer: 010001015 = 111101001000112