This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
Fill in the number with missing zeros on the left
Fill in the number with missing zeros on the right
let\'s make a direct translation from binary to post-binary like this:
011001010.0101002 = 011 001 010. 010 100 = 011(=3) 001(=1) 010(=2). 010(=2) 100(=4) = 312.248
the Final answer: 11001010.01012 = 312.248
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
0∙28+1∙27+1∙26+0∙25+0∙24+1∙23+0∙22+1∙21+0∙20+0∙2-1+1∙2-2+0∙2-3+1∙2-4+0∙2-5+0∙2-6 = 0∙256+1∙128+1∙64+0∙32+0∙16+1∙8+0∙4+1∙2+0∙1+0∙0.5+1∙0.25+0∙0.125+1∙0.0625+0∙0.03125+0∙0.015625 = 0+128+64+0+0+8+0+2+0+0+0.25+0+0.0625+0+0 = 202.312510
got It: 011001010.0101002 =202.312510
Translate the number 202.312510 в octal like this:
the Integer part of the number is divided by the base of the new number system:
202 | 8 | | |
-200 | 25 | 8 | |
2 | -24 | 3 | |
| 1 | | |
|
the Fractional part of the number is multiplied by the base of the new number system:
|
0. | 3125*8 |
2 | .5*8 |
4 | .0*8 |
the result of the conversion was:
202.312510 = 312.248
the Final answer: 11001010.01012 = 312.248