# Transfer 11001010.0101 from binary in octal number system

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This transfer is possible in two ways: direct transfer and using the decimal system.

first, let\'s make a direct transfer.

Fill in the number with missing zeros on the left

Fill in the number with missing zeros on the right

let\'s make a direct translation from binary to post-binary like this:

011001010.0101002 = 011 001 010. 010 100 = 011(=3) 001(=1) 010(=2). 010(=2) 100(=4) = 312.248

the Final answer: 11001010.01012 = 312.248

now let\'s make the transfer using the decimal system.

let\'s translate to decimal like this:

0∙28+1∙27+1∙26+0∙25+0∙24+1∙23+0∙22+1∙21+0∙20+0∙2-1+1∙2-2+0∙2-3+1∙2-4+0∙2-5+0∙2-6 = 0∙256+1∙128+1∙64+0∙32+0∙16+1∙8+0∙4+1∙2+0∙1+0∙0.5+1∙0.25+0∙0.125+1∙0.0625+0∙0.03125+0∙0.015625 = 0+128+64+0+0+8+0+2+0+0+0.25+0+0.0625+0+0 = 202.312510

got It: 011001010.0101002 =202.312510

Translate the number 202.312510 в octal like this:

the Integer part of the number is divided by the base of the new number system:

 202 8 -200 25 8 2 -24 3 1 the Fractional part of the number is multiplied by the base of the new number system: 0. 3125*8 2 .5*8 4 .0*8

the result of the conversion was:

202.312510 = 312.248
the Final answer: 11001010.01012 = 312.248
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