Transfer Deadbeef from hexadecimal in octal number system

This transfer is possible in two ways: direct transfer and using the decimal system.

First we will perform the translation through the decimal system

let\'s translate to decimal like this:

13∙16⁷+14∙16⁶+10∙16⁵+13∙16⁴+11∙16³+14∙16²+14∙16¹+15∙16⁰ = 13∙268435456+14∙16777216+10∙1048576+13∙65536+11∙4096+14∙256+14∙16+15∙1 = 3489660928+234881024+10485760+851968+45056+3584+224+15 = 3735928559₁₀

got It: Deadbeef₁₆ =3735928559₁₀

Translate the number 3735928559₁₀ в octal like this:

the Integer part of the number is divided by the base of the new number system:

3735928559	8
-3735928552	466991069	8
7	-466991064	58373883	8
	5	-58373880	7296735	8
		3	-7296728	912091	8
			7	-912088	114011	8
				3	-114008	14251	8
					3	-14248	1781	8
						3	-1776	222	8
							5	-216	27	8
								6	-24	3
									3

the result of the conversion was:

3735928559₁₀ = 33653337357₈

the Final answer: Deadbeef₁₆ = 33653337357₈

Now we will perform a direct translation.

let\'s do a direct translation from hexadecimal to binary like this:

Deadbeef₁₆ = D e a d b e e f = D_(=1101) e_(=1110) a_(=1010) d_(=1101) b_(=1011) e_(=1110) e_(=1110) f_(=1111) = 11011110101011011011111011101111₂

the Final answer: Deadbeef₁₆ = 11011110101011011011111011101111₂

Fill in the number with missing zeros on the left

let\'s make a direct translation from binary to post-binary like this:

011011110101011011011111011101111₂ = 011 011 110 101 011 011 011 111 011 101 111 = 011₍₌₃₎ 011₍₌₃₎ 110₍₌₆₎ 101₍₌₅₎ 011₍₌₃₎ 011₍₌₃₎ 011₍₌₃₎ 111₍₌₇₎ 011₍₌₃₎ 101₍₌₅₎ 111₍₌₇₎ = 33653337357₈

the Final answer: Deadbeef₁₆ = 33653337357₈

0
(	)	^	←
C	±	÷	X
7	8	9	-
4	5	6	+
1	2	3	=
0		.	=