You specified that your number is in the additional code. For further conversion, you need to get a direct number code. Therefore, let\'s perform the conversion from additional code to direct code.
to do this, first perform the conversion from the additional code to the reverse by subtracting 1 bit, then get the direct code by inverting all the bits except the signed one.
| | . | | |
| 0 | 1 | 0 | twos-complement |
| - | 1 | -1 bit |
| 1 | 0 | 1 | ones complement |
| 1 | 1 | 0 | direct code |
got It:110
let\'s translate to decimal like this:
1∙22+1∙21+0∙20 = 1∙4+1∙2+0∙1 = 4+2+0 = 610
got It: 1102 =610
Translate the number 610 в 2 - false like this:
the Integer part of the number is divided by the base of the new number system:
| 6 | 2 | | |
| -6 | 3 | 2 | |
| 0 | -2 | 1 | |
| 1 | | |
 |
the result of the conversion was:
610 = 1102
the Final answer: 0102 = 1102