This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s do a direct translation from hexadecimal to binary like this:
2EA.F6516 = 2 E A. F 6 5 = 2(=0010) E(=1110) A(=1010). F(=1111) 6(=0110) 5(=0101) = 1011101010.1111011001012
the Final answer: 2EA.F6516 = 1011101010.1111011001012
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
2∙162+14∙161+10∙160+15∙16-1+6∙16-2+5∙16-3 = 2∙256+14∙16+10∙1+15∙0.0625+6∙0.00390625+5∙0.000244140625 = 512+224+10+0.9375+0.0234375+0.001220703125 = 746.96215820312510
got It: 2EA.F6516 =746.96215820312510
Translate the number 746.96215820312510 в binary like this:
the Integer part of the number is divided by the base of the new number system:
| 746 | 2 | | | | | | | | | |
| -746 | 373 | 2 | | | | | | | | |
| 0 | -372 | 186 | 2 | | | | | | | |
| 1 | -186 | 93 | 2 | | | | | | |
| | 0 | -92 | 46 | 2 | | | | | |
| | | 1 | -46 | 23 | 2 | | | | |
| | | | 0 | -22 | 11 | 2 | | | |
| | | | | 1 | -10 | 5 | 2 | | |
| | | | | | 1 | -4 | 2 | 2 | |
| | | | | | | 1 | -2 | 1 | |
| | | | | | | | 0 | | |
 |
the Fractional part of the number is multiplied by the base of the new number system:
 |
| 0. | 962158203125*2 |
| 1 | .92432*2 |
| 1 | .84863*2 |
| 1 | .69727*2 |
| 1 | .39453*2 |
| 0 | .78906*2 |
| 1 | .57813*2 |
| 1 | .15625*2 |
| 0 | .3125*2 |
| 0 | .625*2 |
| 1 | .25*2 |
the result of the conversion was:
746.96215820312510 = 1011101010.11110110012
the Final answer: 2EA.F6516 = 1011101010.11110110012