This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s do a direct translation from hexadecimal to binary like this:
EF16 = E F = E(=1110) F(=1111) = 111011112
the Final answer: EF16 = 111011112
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
14∙161+15∙160 = 14∙16+15∙1 = 224+15 = 23910
got It: EF16 =23910
Translate the number 23910 в binary like this:
the Integer part of the number is divided by the base of the new number system:
| 239 | 2 | | | | | | | |
| -238 | 119 | 2 | | | | | | |
| 1 | -118 | 59 | 2 | | | | | |
| 1 | -58 | 29 | 2 | | | | |
| | 1 | -28 | 14 | 2 | | | |
| | | 1 | -14 | 7 | 2 | | |
| | | | 0 | -6 | 3 | 2 | |
| | | | | 1 | -2 | 1 | |
| | | | | | 1 | | |
 |
the result of the conversion was:
23910 = 111011112
the Final answer: EF16 = 111011112