You specified that your number is in the additional code. For further conversion, you need to get a direct number code. Therefore, let\'s perform the conversion from additional code to direct code.
to do this, first perform the conversion from the additional code to the reverse by subtracting 1 bit, then get the direct code by inverting all the bits except the signed one.
| . | . | . | | |
| 1 | 0 | 0 | 0 | twos-complement |
| | - | 1 | -1 bit |
| 1 | 1 | 1 | 1 | ones complement |
| 1 | 0 | 0 | 0 | direct code |
got It:1000
This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s do a direct translation from binary to hexadecimal like this:
1000.00012 = 1000. 0001 = 1000(=8). 0001(=1) = 8.116
the Final answer: 1000.00012 = 8.116
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
1∙23+0∙22+0∙21+0∙20+0∙2-1+0∙2-2+0∙2-3+1∙2-4 = 1∙8+0∙4+0∙2+0∙1+0∙0.5+0∙0.25+0∙0.125+1∙0.0625 = 8+0+0+0+0+0+0+0.0625 = 8.062510
got It: 1000.00012 =8.062510
Translate the number 8.062510 в hexadecimal like this:
the Fractional part of the number is multiplied by the base of the new number system:
 |
| 0. | 0625*16 |
| 1 | .0*16 |
the result of the conversion was:
8.062510 = 8.116
the Final answer: 1000.00012 = 8.116