This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s translate to decimal like this:
7∙83+1∙82+0∙81+0∙80 = 7∙512+1∙64+0∙8+0∙1 = 3584+64+0+0 = 364810
got It: 71008 =364810
Translate the number 364810 в hexadecimal like this:
the Integer part of the number is divided by the base of the new number system:
| 3648 | 16 | | |
| -3648 | 228 | 16 | |
| 0 | -224 | E | |
| 4 | | |
 |
the result of the conversion was:
364810 = E4016
the Final answer: 71008 = E4016
now let\'s make the transfer using the decimal system.
let\'s do a direct translation from octal to binary like this:
71008 = 7 1 0 0 = 7(=111) 1(=001) 0(=000) 0(=000) = 1110010000002
the Final answer: 71008 = 1110010000002
let\'s do a direct translation from binary to hexadecimal like this:
1110010000002 = 1110 0100 0000 = 1110(=E) 0100(=4) 0000(=0) = E4016
the Final answer: 1110010000008 = E4016