This transfer is possible in two ways: direct transfer and using the decimal system.
First we will perform the translation through the decimal system
let\'s translate to decimal like this:
1∙162+13∙161+2∙160 = 1∙256+13∙16+2∙1 = 256+208+2 = 46610
got It: 1D216 =46610
Translate the number 46610 в octal like this:
the Integer part of the number is divided by the base of the new number system:
| 466 | 8 | | |
| -464 | 58 | 8 | |
| 2 | -56 | 7 | |
| 2 | | |
 |
the result of the conversion was:
46610 = 7228
the Final answer: 1D216 = 7228
Now we will perform a direct translation.
let\'s do a direct translation from hexadecimal to binary like this:
1D216 = 1 D 2 = 1(=0001) D(=1101) 2(=0010) = 1110100102
the Final answer: 1D216 = 1110100102
let\'s make a direct translation from binary to post-binary like this:
1110100102 = 111 010 010 = 111(=7) 010(=2) 010(=2) = 7228
the Final answer: 1D216 = 7228