You specified that your number is in the additional code. For further conversion, you need to get a direct number code. Therefore, let\'s perform the conversion from additional code to direct code.
to do this, first perform the conversion from the additional code to the reverse by subtracting 1 bit, then get the direct code by inverting all the bits except the signed one.
| | | | | | | | | . | | |
| 1 | 0 | 1 | 1 | 0 | 1 | 0 | 1 | 1 | 0 | twos-complement |
| | | | | | | | - | 1 | -1 bit |
| 1 | 0 | 1 | 1 | 0 | 1 | 0 | 1 | 0 | 1 | ones complement |
| 1 | 1 | 0 | 0 | 1 | 0 | 1 | 0 | 1 | 0 | direct code |
got It:1100101010
This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
Fill in the number with missing zeros on the left
let\'s do a direct translation from binary to hexadecimal like this:
0011001010102 = 0011 0010 1010 = 0011(=3) 0010(=2) 1010(=A) = 32A16
the Final answer: 0011001010102 = 32A16
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
0∙211+0∙210+1∙29+1∙28+0∙27+0∙26+1∙25+0∙24+1∙23+0∙22+1∙21+0∙20 = 0∙2048+0∙1024+1∙512+1∙256+0∙128+0∙64+1∙32+0∙16+1∙8+0∙4+1∙2+0∙1 = 0+0+512+256+0+0+32+0+8+0+2+0 = 81010
got It: 0011001010102 =81010
Translate the number 81010 в hexadecimal like this:
the Integer part of the number is divided by the base of the new number system:
| 810 | 16 | | |
| -800 | 50 | 16 | |
| A | -48 | 3 | |
| 2 | | |
 |
the result of the conversion was:
81010 = 32A16
the Final answer: 0011001010102 = 32A16
Print
Addition, multiplication and division of numbers in different number systems
Converting megabits to megabytes
