You specified that your number is in the additional code. For further conversion, you need to get a direct number code. Therefore, let\'s perform the conversion from additional code to direct code.
to do this, first perform the conversion from the additional code to the reverse by subtracting 1 bit, then get the direct code by inverting all the bits except the signed one.
| |
| 0 | twos-complement |
| 1 | -1 bit |
| 1 | ones complement |
| 1 | direct code |
got It:1
let\'s translate to decimal like this:
1∙20+1∙2-1 = 1∙1+1∙0.5 = 1+0.5 = 1.510
got It: 1.12 =1.510