You specified that your number is in the additional code. For further conversion, you need to get a direct number code. Therefore, let\'s perform the conversion from additional code to direct code.
to do this, first perform the conversion from the additional code to the reverse by subtracting 1 bit, then get the direct code by inverting all the bits except the signed one.
| | | . | | |
| 0 | 0 | 1 | 0 | twos-complement |
| | - | 1 | -1 bit |
| 1 | 0 | 0 | 1 | ones complement |
| 1 | 1 | 1 | 0 | direct code |
got It:1110
let\'s translate to decimal like this:
1∙23+1∙22+1∙21+0∙20 = 1∙8+1∙4+1∙2+0∙1 = 8+4+2+0 = 1410
got It: 11102 =1410