This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s make a direct translation from binary to post-binary like this:
1100002 = 110 000 = 110(=6) 000(=0) = 608
the Final answer: 1100002 = 608
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
1∙25+1∙24+0∙23+0∙22+0∙21+0∙20 = 1∙32+1∙16+0∙8+0∙4+0∙2+0∙1 = 32+16+0+0+0+0 = 4810
got It: 1100002 =4810
Translate the number 4810 в octal like this:
the Integer part of the number is divided by the base of the new number system:
| 48 | 8 | |
| -48 | 6 | |
| 0 | | |
 |
the result of the conversion was:
4810 = 608
the Final answer: 1100002 = 608