You specified that your number is in the additional code. For further conversion, you need to get a direct number code. Therefore, let\'s perform the conversion from additional code to direct code.
to do this, first perform the conversion from the additional code to the reverse by subtracting 1 bit, then get the direct code by inverting all the bits except the signed one.
| | | | . | . | . | . | | |
| 1 | 1 | 1 | 1 | 0 | 0 | 0 | 0 | twos-complement |
| | | | | | - | 1 | -1 bit |
| 1 | 1 | 1 | 0 | 1 | 1 | 1 | 1 | ones complement |
| 1 | 0 | 0 | 1 | 0 | 0 | 0 | 0 | direct code |
got It:10010000
This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s do a direct translation from binary to hexadecimal like this:
100100002 = 1001 0000 = 1001(=9) 0000(=0) = 9016
the Final answer: 100100002 = 9016
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
1∙27+0∙26+0∙25+1∙24+0∙23+0∙22+0∙21+0∙20 = 1∙128+0∙64+0∙32+1∙16+0∙8+0∙4+0∙2+0∙1 = 128+0+0+16+0+0+0+0 = 14410
got It: 100100002 =14410
Translate the number 14410 в hexadecimal like this:
the Integer part of the number is divided by the base of the new number system:
| 144 | 16 | |
| -144 | 9 | |
| 0 | | |
 |
the result of the conversion was:
14410 = 9016
the Final answer: 100100002 = 9016