You specified that your number is in the additional code. For further conversion, you need to get a direct number code. Therefore, let\'s perform the conversion from additional code to direct code.
to do this, first perform the conversion from the additional code to the reverse by subtracting 1 bit, then get the direct code by inverting all the bits except the signed one.
| . | . | | |
| 1 | 0 | 0 | twos-complement |
| - | 1 | -1 bit |
| 1 | 1 | 1 | ones complement |
| 1 | 0 | 0 | direct code |
got It:100
This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
Fill in the number with missing zeros on the left
Fill in the number with missing zeros on the right
let\'s do a direct translation from binary to hexadecimal like this:
0100.00102 = 0100. 0010 = 0100(=4). 0010(=2) = 4.216
the Final answer: 0100.00102 = 4.216
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
0∙23+1∙22+0∙21+0∙20+0∙2-1+0∙2-2+1∙2-3+0∙2-4 = 0∙8+1∙4+0∙2+0∙1+0∙0.5+0∙0.25+1∙0.125+0∙0.0625 = 0+4+0+0+0+0+0.125+0 = 4.12510
got It: 0100.00102 =4.12510
Translate the number 4.12510 в hexadecimal like this:
the Fractional part of the number is multiplied by the base of the new number system:
 |
| 0. | 125*16 |
| 2 | .0*16 |
the result of the conversion was:
4.12510 = 4.216
the Final answer: 0100.00102 = 4.216