You specified that your number is in the additional code. For further conversion, you need to get a direct number code. Therefore, let\'s perform the conversion from additional code to direct code.
to do this, first perform the conversion from the additional code to the reverse by subtracting 1 bit, then get the direct code by inverting all the bits except the signed one.
| |
1 | twos-complement |
1 | -1 bit |
1 | ones complement |
1 | direct code |
got It:1
let\'s translate to decimal like this:
1∙20+0∙2-1+0∙2-2+0∙2-3+0∙2-4+1∙2-5 = 1∙1+0∙0.5+0∙0.25+0∙0.125+0∙0.0625+1∙0.03125 = 1+0+0+0+0+0.03125 = 1.0312510
got It: 1.000012 =1.0312510