You specified that your number is in the additional code. For further conversion, you need to get a direct number code. Therefore, let\'s perform the conversion from additional code to direct code.
to do this, first perform the conversion from the additional code to the reverse by subtracting 1 bit, then get the direct code by inverting all the bits except the signed one.
| |
0 | twos-complement |
1 | -1 bit |
1 | ones complement |
1 | direct code |
got It:1
let\'s translate to decimal like this:
1∙20+0∙2-1+0∙2-2+0∙2-3+1∙2-4+1∙2-5+0∙2-6+0∙2-7+1∙2-8+1∙2-9+0∙2-10 = 1∙1+0∙0.5+0∙0.25+0∙0.125+1∙0.0625+1∙0.03125+0∙0.015625+0∙0.0078125+1∙0.00390625+1∙0.001953125+0∙0.0009765625 = 1+0+0+0+0.0625+0.03125+0+0+0.00390625+0.001953125+0 = 1.09960937510
got It: 1.00011001102 =1.09960937510