You specified that your number is in the additional code. For further conversion, you need to get a direct number code. Therefore, let\'s perform the conversion from additional code to direct code.
to do this, first perform the conversion from the additional code to the reverse by subtracting 1 bit, then get the direct code by inverting all the bits except the signed one.
. | . | . | . | | |
1 | 0 | 0 | 0 | 0 | twos-complement |
| | | - | 1 | -1 bit |
1 | 1 | 1 | 1 | 1 | ones complement |
1 | 0 | 0 | 0 | 0 | direct code |
got It:10000
let\'s translate to decimal like this:
1∙24+0∙23+0∙22+0∙21+0∙20 = 1∙16+0∙8+0∙4+0∙2+0∙1 = 16+0+0+0+0 = 1610
got It: 100002 =1610